Question 38Asked in CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026

One of the factors of 5(2x − 4y) + 6(4x² + 16y² − 16xy) − 6 is :5(2x − 4y) + 6(4x² + 16y² − 16xy) − 6 का एक गुणनखंड है :

5(2x − 4y) + 6(4x² + 16y² − 16xy) − 6 का एक गुणनखंड है :
  1. A2x − 4y − 32x − 4y − 3
  2. B4x − 8y + 34x − 8y + 3
  3. C3x − 6y + 13x − 6y + 1
  4. D3x − 6y − 13x − 6y − 1
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Correct answer: (B) 4x − 8y + 34x − 8y + 3

Explanation

Note: the official key accepts both (2) and (4). Put t = 2x − 4y; then 4x² + 16y² − 16xy = t², so the expression is 6t² + 5t − 6 = (2t + 3)(3t − 2) = (4x − 8y + 3) × 2(3x − 6y − 1). Hence both 4x − 8y + 3 and 3x − 6y − 1 are factors.नोट: आधिकारिक उत्तर कुंजी विकल्प (2) और (4) दोनों को स्वीकार करती है। t = 2x − 4y रखिए; तब 4x² + 16y² − 16xy = t², इसलिए व्यंजक 6t² + 5t − 6 = (2t + 3)(3t − 2) = (4x − 8y + 3) × 2(3x − 6y − 1) है। अतः 4x − 8y + 3 और 3x − 6y − 1 दोनों गुणनखंड हैं।

From CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper

This is question 38 of CTET February 2026 Paper 2 Maths & Science, 7 Feb 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.