Question 128Asked in BPSC TRE 3.0 (2024) Mathematics Class 11-12

If a⃗ = 5i − j − 3k and b⃗ = i + 3j − 5k, then a⃗ + b⃗ and a⃗ − b⃗ areयदि a⃗ = 5i − j − 3k तथा b⃗ = i + 3j − 5k, तब a⃗ + b⃗ और a⃗ − b⃗ होंगे

यदि a⃗ = 5i − j − 3k तथा b⃗ = i + 3j − 5k, तब a⃗ + b⃗ और a⃗ − b⃗ होंगे
  1. AParallelसमानान्तर
  2. BPerpendicularलम्बवत्
  3. CInclined with 45°45° पर झुके हुए
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
Show answerHide answer

Correct answer: (B) Perpendicularलम्बवत्

Explanation

(a⃗ + b⃗)·(a⃗ − b⃗) = |a⃗|² − |b⃗|² = (25 + 1 + 9) − (1 + 9 + 25) = 35 − 35 = 0, so the two vectors are perpendicular.(a⃗ + b⃗)·(a⃗ − b⃗) = |a⃗|² − |b⃗|² = (25 + 1 + 9) − (1 + 9 + 25) = 35 − 35 = 0, इसलिए दोनों सदिश लम्बवत् हैं।

From BPSC TRE 3.0 (2024) Mathematics Class 11-12 — Previous Year Paper

This is question 128 of BPSC TRE 3.0 (2024) Mathematics Class 11-12 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.