Question 123Asked in BPSC TRE 2.0 (2023) Mathematics Class 9-10

If c and d are roots of the equation (x – a)(x – b) – k = 0, then a, b are roots of the equationयदि c और d समीकरण (x – a)(x – b) – k = 0 के मूल हैं, तो a, b किस समीकरण के मूल हैं?

यदि c और d समीकरण (x – a)(x – b) – k = 0 के मूल हैं, तो a, b किस समीकरण के मूल हैं?
  1. A(x – c)(x – d) + k = 0(x – c)(x – d) + k = 0
  2. B(x – c)(x – d) – k = 0(x – c)(x – d) – k = 0
  3. C(x – a)(x – c) + k = 0(x – a)(x – c) + k = 0
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (A) (x – c)(x – d) + k = 0(x – c)(x – d) + k = 0

Explanation

Since c and d are the roots, (x - a)(x - b) - k = (x - c)(x - d). Hence (x - c)(x - d) + k = (x - a)(x - b), whose roots are a and b.c, d मूल हैं, अतः (x − a)(x − b) − k = (x − c)(x − d)। इसलिए (x − c)(x − d) + k = (x − a)(x − b), जिसके मूल a और b हैं।

From BPSC TRE 2.0 (2023) Mathematics Class 9-10 — Previous Year Paper

This is question 123 of BPSC TRE 2.0 (2023) Mathematics Class 9-10 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.