Question 55Asked in BPSC TRE 1.0 (2023) Mathematics Class 11-12

If ⁿPᵣ = ⁿPᵣ₊₁ and ⁿCᵣ = ⁿCᵣ₋₁, then the values of n and r are respectivelyयदि ⁿPᵣ = ⁿPᵣ₊₁ और ⁿCᵣ = ⁿCᵣ₋₁, तो n और r के मान हैं, क्रमशः

यदि ⁿPᵣ = ⁿPᵣ₊₁ और ⁿCᵣ = ⁿCᵣ₋₁, तो n और r के मान हैं, क्रमशः
  1. A3 and 23 and 2
  2. B4 and 34 and 3
  3. C1 and 21 and 2
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (A) 3 and 23 and 2

Explanation

ⁿPᵣ₊₁ = ⁿPᵣ·(n − r), so n − r = 1. ⁿCᵣ = ⁿCᵣ₋₁ means r + (r − 1) = n, so n = 2r − 1. Solving gives r = 2 and n = 3.ⁿPᵣ₊₁ = ⁿPᵣ·(n − r), इसलिए n − r = 1। ⁿCᵣ = ⁿCᵣ₋₁ का अर्थ है r + (r − 1) = n, अतः n = 2r − 1। हल करने पर r = 2 और n = 3 मिलता है।

From BPSC TRE 1.0 (2023) Mathematics Class 11-12 — Previous Year Paper

This is question 55 of BPSC TRE 1.0 (2023) Mathematics Class 11-12 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.