Question 43Asked in CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024

If x = k, is the solution of the equation : (x − 4)/7 − 1 = (5 − x)/3 + x, then what is the value of (11k + 18)/(11k − 12) ?यदि x = k, समीकरण

If x = k, is the solution of the equation : (x − 4)/7 − 1 = (5 − x)/3 + x, then what is the value of (11k + 18)/(11k − 12) ?
यदि x = k, समीकरण (x − 4)/7 − 1 = (5 − x)/3 + x का हल है, तो (11k + 18)/(11k − 12) का क्या मान होगा?
  1. A4/94/9
  2. B1/21/2
  3. C3/43/4
  4. D5/85/8
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Correct answer: (D) 5/85/8

Explanation

Multiply by 21: 3(x − 4) − 21 = 7(5 − x) + 21x, so 3x − 33 = 14x + 35 and 11x = −68. Then (11k + 18)/(11k − 12) = (−68 + 18)/(−68 − 12) = −50/−80 = 5/8.21 से गुणा करने पर: 3(x − 4) − 21 = 7(5 − x) + 21x, अर्थात 3x − 33 = 14x + 35 और 11x = −68। तब (11k + 18)/(11k − 12) = (−68 + 18)/(−68 − 12) = −50/−80 = 5/8।

From CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024 — Previous Year Paper

This is question 43 of CTET December 2024 Paper 2 Maths & Science, 14 Dec 2024 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.