If x/y = (−1/3)^(−3) ÷ (2/3)^(−4), then what is the value of (x/y + y/x)^(−1) ?यदि x/y = (−1/3)^(−3) ÷ (2/3)^(−4) है, तो (x/y + y/x)^(−1) का मान क्या है?

Explanation

(−1/3)^(−3) = (−3)³ = −27 and (2/3)^(−4) = (3/2)⁴ = 81/16, so x/y = −27 × 16/81 = −16/3. Then x/y + y/x = −16/3 − 3/16 = −265/48, and its reciprocal is −48/265.(−1/3)^(−3) = (−3)³ = −27 और (2/3)^(−4) = (3/2)⁴ = 81/16, इसलिए x/y = −27 × 16/81 = −16/3। तब x/y + y/x = −16/3 − 3/16 = −265/48 और इसका व्युत्क्रम −48/265 है।