Question 44Asked in CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026

The distance between two parallel sides of a trapezium is 8 cm. If the perimeter of the trapezium is 52 cm and its non-parallel sides are of length 10 cm…किसी समलंब की दोनों समांतर भुजाओं के बीच की दूरी 8 cm है । यदि इस समलंब का परिमाप 52 cm है तथा इसकी प्रत्येक असमांतर भुजा की लंबाई 10 cm है, तो इस समलंब का…

The distance between two parallel sides of a trapezium is 8 cm. If the perimeter of the trapezium is 52 cm and its non-parallel sides are of length 10 cm each, then area of the trapezium (in cm²) is :
किसी समलंब की दोनों समांतर भुजाओं के बीच की दूरी 8 cm है । यदि इस समलंब का परिमाप 52 cm है तथा इसकी प्रत्येक असमांतर भुजा की लंबाई 10 cm है, तो इस समलंब का क्षेत्रफल (cm² में) है :
  1. A192192
  2. B6464
  3. C128128
  4. D9696
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Correct answer: (C) 128128

Explanation

Sum of the parallel sides = 52 - 10 - 10 = 32 cm. Area = 1/2 × 32 × 8 = 128 cm².समांतर भुजाओं का योग = 52 - 10 - 10 = 32 cm। क्षेत्रफल = 1/2 × 32 × 8 = 128 cm²।

From CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026 — Previous Year Paper

This is question 44 of CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.