Question 45Asked in CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026

[(x² + y² – z²)² – (x² – y² + z²)²] / [(y + z)(z – y)] is equal to :[(x² + y² – z²)² – (x² – y² + z²)²] / [(y + z)(z – y)] बराबर है :

[(x² + y² – z²)² – (x² – y² + z²)²] / [(y + z)(z – y)] बराबर है :
  1. A4x²4x²
  2. B–2x²–2x²
  3. C–4x²–4x²
  4. D2x²2x²
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Correct answer: (C) –4x²–4x²

Explanation

Numerator = (a - b)(a + b) with a - b = 2y² - 2z² and a + b = 2x², i.e. 4x²(y - z)(y + z). Dividing by (y + z)(z - y) gives -4x².अंश = (a - b)(a + b), जहाँ a - b = 2y² - 2z² और a + b = 2x², अर्थात् 4x²(y - z)(y + z)। इसे (y + z)(z - y) से भाग देने पर -4x² मिलता है।

From CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026 — Previous Year Paper

This is question 45 of CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.