Question 42Asked in CTET July 2024 Paper 2 Maths & Science, 7 Jul 2024

The number of faces (F), edges (E) and vertices (V) of a polyhedron are 7, 15 and x, respectively. Then, the value of (2F + 3E − 4x) is :किसी बहुफलकी के फलकों (F), किनारों (E) और शीर्षों (V) की संख्याएँ क्रमशः 7, 15 और x हैं। तब, (2F+3E−4x) का मान है :

किसी बहुफलकी के फलकों (F), किनारों (E) और शीर्षों (V) की संख्याएँ क्रमशः 7, 15 और x हैं। तब, (2F+3E−4x) का मान है :
  1. A2020
  2. B1919
  3. C1818
  4. D1717
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Correct answer: (B) 1919

Explanation

Euler's formula F + V − E = 2 gives 7 + x − 15 = 2, so x = 10. Then 2F + 3E − 4x = 14 + 45 − 40 = 19.यूलर सूत्र F + V − E = 2 से 7 + x − 15 = 2, अतः x = 10। तब 2F + 3E − 4x = 14 + 45 − 40 = 19।

From CTET July 2024 Paper 2 Maths & Science, 7 Jul 2024 — Previous Year Paper

This is question 42 of CTET July 2024 Paper 2 Maths & Science, 7 Jul 2024 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.