Question 30Asked in CTET December 2024 Paper 2 Maths & Science, 15 Dec 2024

The value of (0.125 × 57.8 × 0.729) / (0.017 × 0.0081 × 0.25) is equal to(0.125 × 57.8 × 0.729) / (0.017 × 0.0081 × 0.25) का मान बराबर है

(0.125 × 57.8 × 0.729) / (0.017 × 0.0081 × 0.25) का मान बराबर है
  1. A153153
  2. B15301530
  3. C1530015300
  4. D153000153000
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Correct answer: (D) 153000153000

Explanation

Numerator = 0.125 × 57.8 × 0.729 = 5.267025; denominator = 0.017 × 0.0081 × 0.25 = 0.000034425. Simplifying: (0.125/0.25) × (57.8/0.017) × (0.729/0.0081) = 0.5 × 3400 × 90 = 153000.अंश = 0.125 × 57.8 × 0.729 = 5.267025; हर = 0.017 × 0.0081 × 0.25 = 0.000034425। सरल करने पर: (0.125/0.25) × (57.8/0.017) × (0.729/0.0081) = 0.5 × 3400 × 90 = 153000।

From CTET December 2024 Paper 2 Maths & Science, 15 Dec 2024 — Previous Year Paper

This is question 30 of CTET December 2024 Paper 2 Maths & Science, 15 Dec 2024 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.