Question 37Asked in BPSC TRE 2.0 (2023) Mathematics Class 9-10 + 8 more papers

The value of (1 – 1/2)(1 – 1/3)(1 – 1/4) … (1 – 1/n)(1 – 1/2)(1 – 1/3)(1 – 1/4) … (1 – 1/n)

The value of (1 – 1/2)(1 – 1/3)(1 – 1/4) … (1 – 1/n) is
(1 – 1/2)(1 – 1/3)(1 – 1/4) … (1 – 1/n) का मान है
  1. A(n – 1)/n(n – 1)/n
  2. B1/n1/n
  3. C1/(n + 1)1/(n + 1)
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
Show answerHide answer

Correct answer: (B) 1/n1/n

Explanation

The product is (1/2)(2/3)(3/4)…((n-1)/n); every numerator cancels the previous denominator, leaving 1/n.गुणनफल (1/2)(2/3)(3/4)…((n−1)/n) है; प्रत्येक अंश पिछले हर को काट देता है, इसलिए शेष 1/n रहता है।

From BPSC TRE 2.0 (2023) Mathematics Class 9-10 — Previous Year Paper

This is question 37 of BPSC TRE 2.0 (2023) Mathematics Class 9-10 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.

Asked in 9 papers