Question 34Asked in CTET July 2024 Paper 2 Maths & Science, 7 Jul 2024

The value of 52 × 3 ÷ 4 + √441 ÷ 7 × 3 + 5 − 32 ÷ 8 × 12 is :52×3÷4+ 441 ÷7×3+5−32÷8×12 का मान है :

52×3÷4+ 441 ÷7×3+5−32÷8×12 का मान है :
  1. A00
  2. B55
  3. C1515
  4. D2121
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Correct answer: (B) 55

Explanation

By BODMAS: 52 × 3 ÷ 4 = 39; √441 = 21, 21 ÷ 7 × 3 = 9; 32 ÷ 8 × 12 = 48. So 39 + 9 + 5 − 48 = 5.BODMAS के अनुसार: 52 × 3 ÷ 4 = 39; √441 = 21, 21 ÷ 7 × 3 = 9; 32 ÷ 8 × 12 = 48। अतः 39 + 9 + 5 − 48 = 5।

From CTET July 2024 Paper 2 Maths & Science, 7 Jul 2024 — Previous Year Paper

This is question 34 of CTET July 2024 Paper 2 Maths & Science, 7 Jul 2024 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.