Question 105Asked in BPSC TRE 1.0 (2023) Mathematics Class 11-12

If a⃗ = 2î + 5ĵ + 3k̂, b⃗ = 3î + 3ĵ + 6k̂ and c⃗ = 2î + 7ĵ + 4k̂, then |(a⃗ − b⃗) × (c⃗ − a⃗)| isयदि a⃗ = 2î + 5ĵ + 3k̂, b⃗ = 3î + 3ĵ + 6k̂ और c⃗ = 2î + 7ĵ + 4k̂, तो |(a⃗ − b⃗) × (c⃗ − a⃗)| है

यदि a⃗ = 2î + 5ĵ + 3k̂, b⃗ = 3î + 3ĵ + 6k̂ और c⃗ = 2î + 7ĵ + 4k̂, तो |(a⃗ − b⃗) × (c⃗ − a⃗)| है
  1. A1010
  2. B2020
  3. C7070
  4. DMore than one of the aboveउपर्युक्त में से एक से अधिक
  5. ENone of the aboveउपर्युक्त में से कोई नहीं
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Correct answer: (E) None of the aboveउपर्युक्त में से कोई नहीं

Explanation

a⃗ − b⃗ = (−1, 2, −3) and c⃗ − a⃗ = (0, 2, 1). Their cross product is (2·1 − (−3)·2, (−3)·0 − (−1)·1, (−1)·2 − 2·0) = (8, 1, −2), with magnitude √69. This is not among (A)–(C), so the answer is (E).a⃗ − b⃗ = (−1, 2, −3) और c⃗ − a⃗ = (0, 2, 1)। इनका सदिश गुणनफल (2·1 − (−3)·2, (−3)·0 − (−1)·1, (−1)·2 − 2·0) = (8, 1, −2) है, जिसका परिमाण √69 है। यह (A)–(C) में नहीं है, इसलिए उत्तर (E) है।

From BPSC TRE 1.0 (2023) Mathematics Class 11-12 — Previous Year Paper

This is question 105 of BPSC TRE 1.0 (2023) Mathematics Class 11-12 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.