If tan²θ = 1 + 2tan²α, then sin²θ is equal toयदि tan²θ = 1 + 2tan²α, तब sin²θ के बराबर है
यदि tan²θ = 1 + 2tan²α, तब sin²θ के बराबर है
Show answerHide answer
Correct answer: (A) (1 + sin²α)/2(1 + sin²α)/2
Explanation
sin²θ = tan²θ/(1 + tan²θ) = (1 + 2t)/(2 + 2t) with t = tan²α, which simplifies to (1 + sin²α)/2.sin²θ = tan²θ/(1 + tan²θ) = (1 + 2t)/(2 + 2t), जहाँ t = tan²α; इसे सरल करने पर (1 + sin²α)/2 मिलता है।