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Question 36Asked in CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026

The expression 9x² – 12xy + 21x + 4y² – 14y + 12 is factorised as :व्यंजक 9x² – 12xy + 21x + 4y² – 14y + 12 का गुणनखंडन है :

व्यंजक 9x² – 12xy + 21x + 4y² – 14y + 12 का गुणनखंडन है :
  1. A(3x – 2y + 3) (3x – 2y + 4)(3x – 2y + 3) (3x – 2y + 4)
  2. B(3x – 2y + 2) (3x – 2y + 6)(3x – 2y + 2) (3x – 2y + 6)
  3. C(3x + 2y – 2) (3x + 2y – 6)(3x + 2y – 2) (3x + 2y – 6)
  4. D(3x + 2y – 3) (3x + 2y – 4)(3x + 2y – 3) (3x + 2y – 4)
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Correct answer: (A) (3x – 2y + 3) (3x – 2y + 4)(3x – 2y + 3) (3x – 2y + 4)

Explanation

The expression is (3x - 2y)² + 7(3x - 2y) + 12. Putting t = 3x - 2y gives t² + 7t + 12 = (t + 3)(t + 4) = (3x - 2y + 3)(3x - 2y + 4).व्यंजक (3x - 2y)² + 7(3x - 2y) + 12 है। t = 3x - 2y रखने पर t² + 7t + 12 = (t + 3)(t + 4) = (3x - 2y + 3)(3x - 2y + 4)।

From CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026 — Previous Year Paper

This is question 36 of CTET February 2026 Paper 2 Maths & Science, 1 Mar 2026 — Previous Year Paper. See all questions of this paper with answers, or attempt the paper as a timed online test to get your score and all-India rank.