The principal value of (−1)^(−2i/π) is(−1)^(−2i/π) का प्रिन्सिपल मान है
(−1)^(−2i/π) का प्रिन्सिपल मान है
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Correct answer: (B) e²e²
Explanation
(−1)^w = exp(w · Log(−1)) = exp(w · iπ). With w = −2i/π this is exp((−2i/π)(iπ)) = e².(−1)^w = exp(w · Log(−1)) = exp(w · iπ)। w = −2i/π लेने पर यह exp((−2i/π)(iπ)) = e² है।