The value of (tan⁻¹5 − tan⁻¹3 + tan⁻¹(7/9)) is(tan⁻¹5 − tan⁻¹3 + tan⁻¹(7/9)) का मान है

Explanation

tan⁻¹5 − tan⁻¹3 = tan⁻¹(2/16) = tan⁻¹(1/8). Then tan⁻¹(1/8) + tan⁻¹(7/9) = tan⁻¹[(1/8 + 7/9)/(1 − 7/72)] = tan⁻¹[(65/72)/(65/72)] = tan⁻¹1 = π/4.tan⁻¹5 − tan⁻¹3 = tan⁻¹(2/16) = tan⁻¹(1/8)। फिर tan⁻¹(1/8) + tan⁻¹(7/9) = tan⁻¹[(1/8 + 7/9)/(1 − 7/72)] = tan⁻¹[(65/72)/(65/72)] = tan⁻¹1 = π/4।