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FreePrevious Year Paper· TRE 2.0 (2023)

BPSC TRE 2.0 (2023) Physics Class 11-12 — Previous Year Paper

Attempt BPSC TRE 2.0 (2023) Physics Class 11-12 — Previous Year Paper online for free with the official answer key: 149 questions, 150 minutes, 1/3 negative marking. Questions in English and Hindi with instant score, all-India rank and detailed solutions on UTpaper.

  • 149 Questions
  • 149 Marks
  • 150 Minutes
  • English + Hindi
Attempt test free →Questions with answers

About BPSC TRE 2.0 (2023) Physics Class 11-12 — Previous Year Paper

This is the actual BPSC TRE 2.0 (2023) Physics Class 11-12 — Previous Year Paper converted into an online test with the official answer key. Attempt it with the real time limit of 150 minutes to see exactly how you would score in the BPSC TRE exam, then go through the solutions to fix weak topics. It is one of 3 free tests in the BPSC TRE Physics (Class 11-12) Mock Test & PYQ.

Section-wise pattern

SectionQuestionsMarksCounts for merit?
Language3030Qualifying only (30% to pass)
General Studies4040Yes
Physics7979Yes

Sample questions from this test

Q71
Laser light beamed at the moon takes 2·56 seconds to return after reflection at the moon's surface. The radius of the lunar orbit around the earth would be
  1. A3·84 × 10⁵ km
  2. B3·84 × 10⁵ m
  3. C0·384 × 10⁵ km
  4. DMore than one of the above
  5. ENone of the above
Show answer
Q72
The technique used to measure large time intervals is
  1. Asolar eclipse
  2. Bradioactive dating
  3. Crelativistic technique
  4. DMore than one of the above
  5. ENone of the above
Show answer
Q73
The voltage across a lamp is V = (6·0 ± 0·1) volt, and current passing through it is I = (4 ± 0·2) ampere. Considering the power consumed P = VI, by the electric lamp within error limit would be
  1. A(24 ± 1·6) watt
  2. B(24 ± 16) watt
  3. C(0·24 ± 1·6) watt
  4. DMore than one of the above
  5. ENone of the above
Show answer
Q74
The nearest star to our solar system is 4·29 light-year away. How much is this distance in terms of parsecs?
  1. A1323 parsecs
  2. B1·323 parsecs
  3. C132·3 parsecs
  4. DMore than one of the above
  5. ENone of the above
Show answer
Q75
A capacitor of capacitance C = (2·0 ± 0·1) μF is charged to a voltage V = (20 ± 0·5) volts. The total charge on the capacitor within the error would be
  1. A(40·0 ± 3·0) × 10⁻⁶ C
  2. B(40·0 ± 0·3) × 10⁻⁶ C
  3. C(40·0 ± 3·0) × 10⁶ C
  4. DMore than one of the above
  5. ENone of the above
Show answer

Attempt the full test to answer all 149 questions under the real time limit, or read all 149 questions with answers.

How to attempt

  1. Click “Attempt test free” and sign in with Google or your UTpaper account.
  2. The timer starts at 150 minutes. Use the question palette to move between questions and mark questions for review.
  3. Submit when done. You get your score, accuracy, section-wise marks and all-India rank instantly, with the solution for every question.

Frequently asked questions

Is the BPSC TRE 2.0 (2023) Physics Class 11-12 — Previous Year Paper free to attempt?
Yes. The test is completely free on UTpaper. Sign in with Google or create a free account, click Attempt test, and your score, rank and solutions appear as soon as you submit.
How many questions and how much time does this test have?
The test has 149 questions for 149 marks and must be finished in 150 minutes. Each wrong answer deducts 1/3 mark.
Are the answers in this BPSC TRE previous year paper official?
Yes. The answer key follows the official final answer key released by the exam board. Where an official answer is debatable, the explanation says so.
What are the sections in this test?
The test has 3 sections: Language (30 questions), General Studies (40 questions) and Physics (79 questions). Language is qualifying only: you must reach the pass mark, but those marks are not added to your total. Every question also has a “Question not attempted” option; a question left completely blank is penalised like a wrong answer, as in the real exam.
Can I reattempt the test and see solutions?
Yes. After submitting you see the correct answer and explanation for every question, your accuracy, section-wise marks and all-India rank. You can reattempt as many times as you like.

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