570 Computer Science questions asked in UGC NET previous year papers, each with the correct answer and explanation. Read them free on UTpaper, or attempt the full papers as timed online tests.
Q401UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
The ISO quality assurance standard that applies to software Engineering is
AISO 9000: 2004
BISO 9001: 2000
CISO 9002: 2001
DISO 9003: 2004
Show answerHide answer
Correct answer: (B) ISO 9001: 2000
Explanation
The 9001 : 2000 is the quality assurance standard that applies to software engineering. The standard contains 20 requirement that must be present for an effective quality assurance system.
Q402UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Which of the following are external qualities of a software product?
External qualities of a software product: - Correctness - Reliability - Robustness - Efficiency - Usability Internal qualities of a software product - Maintainability - Reusability - Portability - Interoperability
Q403UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Which of the following tag in HTML is used to surround information, such as signature of the person who created the page?
A<body> </body>
B<address> </address>
C<strong> </strong>
D<em> </em>
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Correct answer: (B) <address> </address>
Explanation
The <address> tag is used to surround information, such as the signature of the person who created the page or the address of the organization the page is about. The <body> tag defines the document is body. The <em> tag defines emphasized text. The <strong> tag defines important text.
Q404UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Which of the following is not used in standard JPEG image compression?
AHuffman coding
BRun length encoding
CZig-zag scan
DK-L Transform
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Correct answer: (D) K-L Transform
Explanation
Standard JPEG uses the DCT, zig-zag scan, run-length encoding and Huffman coding. The K-L (Karhunen-Loeve) transform is not used in standard JPEG compression.
Q405UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
If the histogram of an image is clustered towards origin on X-axis of a histogram plot then it indicates that the image is
ADark
BGood contrast
CBright
DVery low contrast
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Correct answer: (A) Dark
Explanation
If the histogram of an image is clustered towards the origin (low intensity values) on the X-axis, the image is dark. If it is clustered towards the high end of the X-axis, the image is bright.
Q406UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
In Artificial Intelligence, a semantic network
AIs a graph-based method of knowledge representation where nodes represent concepts and arcs represent relations between concepts.
BIs a graph-based method of knowledge representation where nodes represent relations between concepts and arcs represent concepts.
CRepresents an entity as a set of slots and associated rules.
DIs a subset of first-order logic.
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Correct answer: (A) Is a graph-based method of knowledge representation where nodes represent concepts and arcs represent relations between concepts.
Explanation
In Artificial Intelligence, a semantic network is a graph-based method of knowledge representation where nodes represent concepts, instances or events and arcs (links) represent relationships between them, such as is-a, part-of and kind-of.
Q407UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Given a Turing Machine
M = ({q₀, q₁}, {0, 1}, {0, 1, B}, δ, B, {q₁})
Where δ is a transition function defined as
δ(q₀, 0) = (q₀, 0, R)
δ(q₀, B) = (q₁, B, R)
The language L(M) accepted by turing machine is given as:
A0* 1*
B00*
C10*
D1*0*
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Correct answer: (B) 00*
Explanation
The machine moves right over 0s and accepts on reaching the blank, so it accepts 0*. 00* is a subset of 0*, so the machine accepts all strings of 00*; the only other accepted string is the empty string ε.
Q408UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Let G = (V, T, S, P) be a context-free grammar such that every one of its productions is of the form A → v, with |v| = k > 1. The derivation tree for any string W ∈ L(G) has a height such that
Each internal node of the derivation tree has exactly k children. The tree is shortest when it is complete, giving h ≥ logₖ |W|, and tallest when each level has only one internal node, giving h ≤ (|W| – 1)/(k – 1). So logₖ |W| ≤ h ≤ (|W| – 1)/(k – 1).
Q409UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Match the following with reference to Functional programming history:
List-I
A. Lambda calculus
B. Lambda calculus as programming language
C. Lazy evaluation
D. Type classes
List-II
1. Church, 1932
2. Wordsworth, 1970
3. Haskel, 1990
4. Mecarthy, 1960
Codes: A B C D
A4 1 3 2
B1 4 2 3
C3 2 4 1
D2 1 4 3
Show answerHide answer
Correct answer: (B) 1 4 2 3
Explanation
Lambda calculus was introduced by Alonzo Church (1932). Its use as a programming language came with LISP by McCarthy (1960). Lazy evaluation was introduced by Wadsworth (1970). Type classes were introduced in Haskell (1990). So A-1, B-4, C-2, D-3.
Q410UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Criticism free idea generation is a factor of ______.
ADecision Support System
BGroup Decision Support System
CEnterprise Resource Support System
DArtificial Intelligence
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Correct answer: (B) Group Decision Support System
Explanation
Criticism-free idea generation is a feature of a group decision support system (GDSS).
Q411UGC NET Computer Science, August 2016 (Paper II & III, Selected Questions)
Which of the following is a source coding technique?
AHuffman coding
BArithmetic coding
CRun-length coding
DDPCM
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Correct answer: (D) DPCM
Explanation
DPCM (differential pulse code modulation) converts the analog source signal into a digital signal, i.e. it is a source coding technique.
Q412UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Convert the octal number 0.4051 into its equivalent decimal number.
Q413UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
The hexadecimal equivalent of the octal number 2357 is :
A2EE
B2FF
C4EF
D4FE
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Correct answer: (C) 4EF
Explanation
(2357)₈ = (010 011 101 111)₂. Grouping into 4 bits from right to left: 0100 1110 1111, so it is (4EF)₁₆.
Q414UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
If X is a binary number which is power of 2, then the value of X & (X – 1) is :
A11.......11
B00.......00
C100......0
D000.......1
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Correct answer: (B) 00.......00
Explanation
Let x = 2³ = 8 = 1000; then x – 1 = 7 = 0111. Now x & (x – 1) = 0000 (& is bitwise AND: a result bit is 1 only if both compared bits are 1, otherwise 0). So for any power of 2 the result is all zeros.
Q415UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
A binary 3-bit down counter uses J-K flip-flops, FFᵢ with inputs Jᵢ, Kᵢ and outputs Qᵢ, i = 0, 1, 2 respectively. The minimized expression for the input from following, is
I. J₀ = K₀ = 0
II. J₀ = K₀ = 1
III. J₁ = K₁ = Q₀
IV. J₁ = K₁ = Q₀'
V. J₂ = K₂ = Q₁ Q₀
VI. J₂ = K₂ = Q₁' Q₀'
AI, III, V
BI, IV, VI
CII, III, V
DII, IV, VI
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Correct answer: (D) II, IV, VI
Explanation
For a 3-bit down counter using J-K flip-flops (in toggle mode): J₀ = K₀ = 1, J₁ = K₁ = Q₀' and J₂ = K₂ = Q₁' Q₀'. So II, IV and VI.
Q416UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Match the following :
List-I
A. Absurd
B. Ambiguous
C. Axiom
D. Conjecture
List-II
i. Clearly impossible being contrary to some evident truth
ii. Capable of more than one interpretation or meaning
iii. An assertion that is accepted and used without a proof
iv. An opinion preferably based on some experience or wisdom
Codes :
A B C D
Ai ii iii iv
Bi iii iv ii
Cii iii iv i
Dii i iii iv
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Correct answer: (A) i ii iii iv
Explanation
Absurd means utterly or obviously senseless, illogical or untrue, i.e. contrary to all reason or evident truth (A–i). Ambiguous means open to more than one meaning or interpretation (B–ii). Axiom is a self-evident truth that requires no proof, a universally accepted principle (C–iii). Conjecture is an opinion or theory formed without sufficient evidence, e.g. based on past experience (D–iv).
Q417UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
In propositional logic if (P → Q) ∧ (R → S) and (P ∧ R) are two premises such that
(P → Q) ∧ (R → S)
P ∨ R
----------
Y
Y is the premise :
AP ∨ R
BR ∨ S
CQ ∨ R
DQ ∨ S
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Correct answer: (D) Q ∨ S
Explanation
Given premises (P → Q) ∧ (R → S) and (P ∨ R). (P → Q) = ¬P ∨ Q and (R → S) = ¬R ∨ S. Resolving with P ∨ R, ¬P with P and ¬R with R resolve out, leaving the disjunction Q ∨ S (constructive dilemma). So Q ∨ S is correct.
Q418UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Consider a sequence F₀₀ defined as :
F₀₀(0) = 1, F₀₀(1) = 1
F₀₀(n) = (10*F₀₀(n – 1) + 100) / F₀₀(n – 2) for n ≥ 2
Then what shall be the set of values of the sequence F₀₀ ?
A(1, 110, 1200)
B(1, 110, 600, 1200)
C(1, 2, 55, 110, 600, 1200)
D(1, 55, 110, 600, 1200)
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Correct answer: (A) (1, 110, 1200)
Explanation
F₀₀(0) = 1, F₀₀(1) = 1. F₀₀(2) = (10*1 + 100)/1 = 110, F₀₀(3) = (10*110 + 100)/1 = 1200, F₀₀(4) = (10*1200 + 100)/110 = 110, F₀₀(5) = (10*110 + 100)/1200 = 1, F₀₀(6) = (10*1 + 100)/110 = 1, and the values repeat. So the set of values is (1, 110, 1200).
Q419UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Consider a Hamiltonian Graph G with loops or parallel edges and with |V(G)| = n ≥ 3. Then which of the following is true?
Adeg(v) ≥ n/2 for each vertex v.
B|E(G)| ≥ (1/2)(n – 1)(n – 2) + 2
Cdeg(v) + deg(w) ≥ n whenever v and w are not connected by an edge.
DAll of the above
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Correct answer: (D) All of the above
Explanation
By Dirac's theorem, deg(v) ≥ n/2 for every vertex; by Ore's theorem, deg(v) + deg(w) ≥ n for every pair of non-adjacent vertices v and w; and a graph with |E(G)| ≥ (1/2)(n – 1)(n – 2) + 2 edges is Hamiltonian. So all of the above.
Q420UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Consider the following assembly language instructions :
mov al, 15
mov ah, 15
xor al, al
mov cl, 3
shr ax, cl
add al, 90H
adc ah, 0
What is the value in ax register after execution of above instructions?
Q421UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
The contents of register (BL) and register (AL) of 8085 microprocessor are 49H and 3AH respectively. The contents of Al, the status of carry flag (CF) and sign flag (SF) after executing 'SUB AL, BL' assembly language instruction, are
AAL = 0FH; CF = 1; SF = 1
BAL = F0H; CF = 0; SF = 0
CAL = F1H; CF = 1; SF = 1
DAL = 1FH; CF = 1; SF = 1
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Correct answer: (C) AL = F1H; CF = 1; SF = 1
Explanation
(AL) = 3AH = 00111010, (BL) = 49H = 01001001. AL – BL = 11110001, so (AL) = F1H, CF = 1, SF = 1. The carry (borrow) flag is set since the first operand is less than the second; the result is negative, so the sign flag is set.
Q422UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following statements is false?
(A) Optimal binary search tree construction can be performed efficiently using dynamic programming.
(B) Breadth-first search cannot be used to find connected components of a graph.
(C) Given the prefix and postfix walks of a binary tree, the tree cannot be re-constructed uniquely.
(D) Depth-first-search can be used to find the connected components of a graph.
AA
BB
CC
DD
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Correct answer: (B) B
Explanation
Statement B is false: breadth-first search can be used to find the connected components of a graph, just like depth-first search. Optimal binary search tree construction is a well-known dynamic programming application, and given only the prefix and postfix walks of a binary tree, the tree cannot be reconstructed uniquely.
Q423UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
If h is chosen from a universal collection of hash functions and is used to hash n keys into a table of size m, where n ≤ m, the expected number of collisions involving a particular key x is less than .........
A1
B1/n
C1/m
Dn/m
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Correct answer: (A) 1
Explanation
Let Xᵢ = 1 if key x collides with the i-th other key, else 0. For a universal hash family, a given pair collides with probability 1/m, so E(Xᵢ) = 1/m. Summing over the other (n – 1) keys, the expected number of collisions involving x is (n – 1)/m. Since n ≤ m, this is less than 1.
Q424UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following is true for computation time in insertion, deletion and finding maximum and minimum element in a sorted array?
In a sorted array, insertion and deletion take O(n) in the worst case (elements must be shifted), while the minimum and maximum are always at the two ends, so finding them takes O(1).
Q425UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
The order of a leaf in a B+ tree is the maximum number of children it can have. Suppose that block size is 1 kilobyte, the child pointer takes 7 bytes long and search field value takes 14 bytes long. The order of the leaf node is ..........
A16
B63
C64
D65
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Correct answer: (A) 16
Explanation
Data pointer = child pointer + search field value = 7 + 14 = 21 bytes. Maximum number of entries = 1 KB/21 bytes = 1024/21 ≈ 48.76. The book picks 16 since all other options are greater than 48.
Q426UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following is a valid heap? (Each tree is a complete binary tree given in level order, left to right.)
(A) 16, 14, 10, 4, 7, 9, 3, 2, 8, 1
(root 16; children of 16: 14, 10; children of 14: 4, 7; children of 10: 9, 3; children of 4: 2, 8; child of 7: 1)
(B) 16, 14, 10, 8, 7, 9, 3, 2, 4, 1
(root 16; children of 16: 14, 10; children of 14: 8, 7; children of 10: 9, 3; children of 8: 2, 4; child of 7: 1)
(C) 16, 14, 10, 8, 1, 9, 3, 2, 4, 7
(root 16; children of 16: 14, 10; children of 14: 8, 1; children of 10: 9, 3; children of 8: 2, 4; child of 1: 7)
(D) 16, 14, 3, 4, 1, 9, 10, 8, 2, 7
(root 16; children of 16: 14, 3; children of 14: 4, 1; children of 3: 9, 10; children of 4: 8, 2; child of 1: 7)
AA
BB
CC
DD
Show answerHide answer
Correct answer: (B) B
Explanation
(A) fails the max-heap property (4 has child 8). (B) is a valid max heap because every parent ≥ its children. (C) fails (1 has child 7). (D) fails (3 has children 9 and 10; 4 has child 8; 1 has child 7).
Q427UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
How many multiples of 6 are there between the following pairs of numbers?
0 and 100 and –6 and 34
A16 and 6
B17 and 6
C17 and 7
D16 and 7
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Correct answer: (A) 16 and 6
Explanation
(i) Multiples of 6 between 1 and 100 = ⌊100/6⌋ = 16 (the book counts 16 for 0 to 100). (ii) Multiples of 6 between 0 and 34 = ⌊34/6⌋ + 1 (for 0) = 5 + 1 = 6.
Q428UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following strings would match the regular expression : p+[3 – 5]*[xyz]?
I. p443y
II. p6y
III. 3xyz
IV. p35z
V. p353535x
VI. ppp5
AI, III and VI only
BIV, V and VI only
CII, IV and V only
DI, IV and V only
Show answerHide answer
Correct answer: (D) I, IV and V only
Explanation
p+[3–5]*[xyz] = one or more p, then any number of 3, 4 or 5, then exactly one of x, y, z.
(I) p443y → matched
(II) p6y → not matched, since 6 cannot be used
(III) 3xyz → not matched, string must start with p
(IV) p35z → matched
(V) p353535x → matched
(VI) ppp5 → not matched, string must end with x, y or z
Q429UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following statements (s) regarding a linker software is/are true?
I. A function of a linker is to combine several object modules into a single load module.
II. A function of a linker is to replace absolute references in an object module by symbolic references to locations in other modules
AOnly I
BOnly II
CBoth I and II
DNeither I nor II
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Correct answer: (A) Only I
Explanation
Statement I is true: a linker combines several object modules into a single load module. Statement II is wrong: a linker replaces symbolic references by addresses (it generates relocatable addresses), not absolute references by symbolic ones.
Q430UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
There are three processes P1, P2 and P3 sharing a semaphore for synchronizing a variable. Initial value of semaphore is one. Assume that negative value of semaphore tells us how many processes are waiting in queue. Processes access the semaphore in following order :
(A) P2 needs to access
(B) P1 needs to access
(C) P3 needs to access
(D) P2 exits critical section
(E) P1 exits critical section
The final value of semaphore will be :
A0
B1
C–1
D–2
Show answerHide answer
Correct answer: (A) 0
Explanation
Initial value S = 1.
(1) P2 needs to access: S = 0 (no one waiting)
(2) P1 needs to access: S = –1 (one process waiting)
(3) P3 needs to access: S = –2 (two processes waiting)
(4) P2 exits critical section: S = –1 (one process waiting)
(5) P1 exits critical section: S = 0 (no process waiting)
Q431UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
In a paging system, it takes 30 ns to search translation Look-a-side buffer (TLB) and 90 ns to access the main memory. If the TLB hit ratio is 70%, the effective memory access time is :
A48ns
B147ns
C120ns
D84ns
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Correct answer: (B) 147ns
Explanation
TLB hit ratio 70%, TLB search 30 ns, memory access 90 ns. On a hit, the page is found in the TLB (30 ns); on a miss, the TLB is searched and the page table read from memory (30 + 90 ns); then 90 ns to access the data.
Total = (0.7 × 30) + (0.3 × (90 + 30)) + 90 = 21 + 36 + 90 = 147 ns
Q432UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Match the following w.r.t. Input/Output management :
List-I
A. Device controller
B. Device driver
C. Interrupt handler
D. Kernel I/O subsystem
List-II
i. Extracts information from the controller register and store it in data buffer
ii. I/O scheduling
iii. Performs data transfer
iv. Processing of I/O request
Codes :
A B C D
Aiii iv i ii
Bii i iv iii
Civ i ii iii
Di iii iv ii
Show answerHide answer
Correct answer: (D) i iii iv ii
Explanation
The correct match: A. Device controller – i. Extracts information from the controller register and stores it in data buffer; B. Device driver – iii. Performs data transfer; C. Interrupt handler – iv. Processing of I/O request; D. Kernel I/O subsystem – ii. I/O scheduling.
Q433UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following scheduling algorithms may cause starvation?
A. First-come-first-served
B. Round Robin
C. Priority
D. Shortest process next
E. Shortest remaining time first
AA, C and E
BC, D and E
CB, D, and E
DB, C and D
Show answerHide answer
Correct answer: (B) C, D and E
Explanation
(1) First come – first served – No starvation (2) Round robin – No starvation (3) Priority – starvation if higher priority process called again & again lower priority starves (4) Shortest process next = starvation possible (5) Shortest remaining time first = starvation possible
Q434UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Distributed operating system consist of :
ALoosely coupled O.S. software on a loosely coupled hardware
BLoosely coupled O.S. Software on a tightly coupled hardware
CTightly coupled O.S. Software on a loosely coupled hardware
DTightly coupled O.S. software on a tightly coupled hardware
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Correct answer: (C) Tightly coupled O.S. Software on a loosely coupled hardware
Explanation
A distributed operating system is usually defined as running on more loosely coupled hardware. There is no shared memory, but provides a single memory by tightly coupled software.
Q435UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
______ refers loosely to the process of semi-automatically analyzing large databases to find useful patterns
ADatamining
BData warehousing
CDBMS
DData mirroring
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Correct answer: (A) Datamining
Explanation
The practice of examining large pre-existing databases in order to generate new information is data mining. It refers loosely to the process of semi-automatically analyzing large databases to find useful patterns.
Q436UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following statements is/are true w.r.t. Enterprise Resource planning (ERP)?
(A) ERP automates and integrates majority of business processes
(B) ERP provides access to information in a Real Time Environment.
(C) ERP is inexpensive to implement.
A(A), (B) and (C) are false
B(A) and (B) false; (C) true
C(A) and (B) true; (C) false
D(A) true; (B) and (C) are false
Show answerHide answer
Correct answer: (C) (A) and (B) true; (C) false
Explanation
(1) ERP automates and integrates majority of business – true (2) ERP provides access to information in a real time environment – true (3) ERP is inexpensive to implement – false
Q437UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
An attribute A of data type varchar (20) has value 'Ram' and the attribute B of data type char (20) has value 'Sita' in oracle. The attribute A has ______ memory spaces and B has ______ memory spaces.
A20, 20
B3, 20
C3, 4
D20, 4
Show answerHide answer
Correct answer: (B) 3, 20
Explanation
CHAR and VARCHAR are both declared with a maximum length, but a CHAR column is fixed to the declared length (padded with spaces), while VARCHAR(20) uses only as much space as the stored value. So A ('Ram') needs 3 spaces and B ('Sita') needs 20.
Q438UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Integrity constraints ensure that change made to the database by authorized users do not result into loss of data consistency. Which of the following statement (s) is (are) true w.r.t. the examples of integrity constraints?
(A) An instructor Id. No. cannot be null, provided Instructor Id No. being primary key.
(B) No two citizens have same Adhar-Id
(C) Budget of a company must be zero
A(A), (B) and (C) are true
B(A) false, (B) and (C) are true
C(A) and (B) are true; (C) false
D(A), (B) and (C) are false
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Correct answer: (C) (A) and (B) are true; (C) false
Explanation
An instructor Id. No. cannot be null when it is the primary key – valid integrity constraint. No two citizens have the same Aadhaar-Id – valid. But 'the budget of a company must be zero' is not a valid integrity constraint. So (A) and (B) are true and (C) is false.
Q439UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Let M and N be two entities in an E-R diagram with simple single value attributes. R₁ and R₂ are two relationship between M and N, where as : R₁ is one-to-many and R₂ is many-to-many. The minimum number of tables required to represent M, N, R₁ and R₂ in the relational model are _____
A4
B6
C7
D3
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Correct answer: (D) 3
Explanation
Two tables are created for entities M and N, and a third table for the many-to-many relationship R₂. R₁ (one-to-many) needs no separate table: the primary key of the 'one' side is placed as a foreign key in the 'many' side. So the minimum is 3 tables.
Q440UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Consider a schema R(MNPQ) and functional dependencies M → N, P → Q. Then the decomposition of R into R₁ (MN) and R₂(PQ) is ______
ADependency preserving but not lossless join
BDependency preserving and lossless join
CLossless join but not dependency preserving
DNeither dependency preserving nor lossless join
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Correct answer: (A) Dependency preserving but not lossless join
Explanation
With R(MNPQ), M → N and P → Q, the decomposition into R₁(MN) and R₂(PQ) clearly preserves both dependencies, but it is not lossless because R₁ and R₂ have no common attribute, so R cannot be recovered by joining them.
Q441UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Match the following layers and Protocols for a user browsing with SSL :
List-I
A. Application of layer
B. Transport layer
C. Network layer
D. Datalink layer
List-II
i. TCP
ii. IP
iii. PPP
iv. HTTP
Codes :
A B C D
Aiv i ii iii
Biii ii i iv
Cii iii iv i
Diii i iv ii
Show answerHide answer
Correct answer: (A) iv i ii iii
Explanation
The correct match: A. Application layer – iv. HTTP; B. Transport layer – i. TCP; C. Network layer – ii. IP; D. Datalink layer – iii. PPP.
Q442UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
A packet whose destination is outside the local TCP/IP network segment is sent to______
AFile server
BDNS server
CDHCP server
DDefault gateway
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Correct answer: (D) Default gateway
Explanation
Default gateway serves an access point or IP router that a networked uses to send information to a computer in another network or the internet. Default simply means that this gateway is used by default, unless an application specifies another gateway.
Q443UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Distance vector routing algorithm is a dynamic algorithm. The routing tables in distance vector routing algorithm are updated ______
AAutomatically
BBy server
CBy exchanging information with neighbor nodes
DWith back up database
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Correct answer: (C) By exchanging information with neighbor nodes
Explanation
A distance vector routing protocol requires that a router inform its neighbors about its topology changes periodically.
Q444UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Software Engineering is an engineering discipline that is concerned with :
AHow computer systems work
BTheories and methods that underline computers and software systems
CAll aspects of software production
DAll aspects of computer-based system development, including hardware, software and process engineering
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Correct answer: (C) All aspects of software production
Explanation
Software engineering is an engineering discipline that is concerned with all aspects of software production.
Q445UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
The prototyping model of software development is :
AA reasonable approach when requirements are well-defined
BA useful approach when a customer cannot define requirements clearly
CThe best approach to use for projects with large development teams
DA risky model that rarely produces a meaningful product
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Correct answer: (B) A useful approach when a customer cannot define requirements clearly
Explanation
This model allows for the creation of a preliminary version (prototype) of the software, which can be refined iteratively based on user feedback until satisfactory version is achieved. Clarifies Requirements– The prototyping process helps customers visualize and understand what the final product will look like and how it will function. Reduce Risk– By identifying potential issues early on through prototyping, developers can avoid costly rework and delays later in the development cycle.
Q446UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following is not one of three software product aspects addressed by Mccall's software quality factors?
AAbility to undergo change
BAdaptability to new environments
COperational characteristics
DProduction costs and scheduling
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Correct answer: (D) Production costs and scheduling
Explanation
Mccalls's software quality factors. (1) ability to undergo change (2) Adaptability to new environments (3) Operational characteristics but production costs & scheduling is not the aspect of quality factor.
Q447UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following statement(s) is/are true with respect to software architecture?
S1 : Coupling is a measure of how well the grouped together in a module belong together logically.
S2 : Cohesion is a measure of the degree of interaction between software modules
S3 : If coupling is low and cohesion is high then it is easier to change one module without affecting others.
AOnly S1 and S2
BOnly S3
CAll of S1, S2 and S3
DOnly S1
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Correct answer: (B) Only S3
Explanation
S1 and S2 swap the definitions: cohesion measures how well the things grouped in a module belong together, and coupling measures the degree of interaction between modules. S3 is true: if coupling is low and cohesion is high, it is easier to change one module without affecting others.
Q448UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
A software design pattern used to enhance the functionality of an object at run-time is :
AAdapter
BDecorator
CDelegation
DProxy
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Correct answer: (B) Decorator
Explanation
In object-oriented programming, the decorator pattern (also known as wrapper) is a design pattern that allows behaviour to be added to an individual object, statically or dynamically at run-time, without affecting the behaviour of other objects of the same class.
Q449UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following storage classes have global visibility in C/C++?
AAuto
BExtern
CStatic
DRegister
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Correct answer: (B) Extern
Explanation
extern declares variables/functions with external linkage, giving them global visibility across files. It is the default storage class of all global variables and functions.
Q450UGC NET Computer Science, June 2017 (Paper II & III, Selected Questions)
Which of the following operators cannot be overloaded in C/C++?
ABitwise right shift assignment
BAddress of
CIndirection
DStructure reference
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Correct answer: (D) Structure reference
Explanation
Structure reference refers to the dot operator (.), which is one of the operators that cannot be overloaded in C++. The other options (>>=, unary & and unary *) can be overloaded for custom types in C++.
How to use these UGC NET Computer Science questions
Every question here was asked in a real UGC NET paper; the paper and shift are shown on the card, and the number opens the question on its own page. Try each one before tapping Show answer, then attempt the full UGC NET papers as timed tests to check your speed under exam conditions.